Plotting the Turning Points

Oct 13, 2025 by miodeya.com 148 views

Introduction

In this article, we will delve into the analysis of the function h(x) = x + 1/x. We will explore the intervals where the graph of the function is increasing or decreasing and identify its turning points. This analysis will provide valuable insights into the behavior of the function and its graph.

Function Analysis

The given function is h(x) = x + 1/x. To analyze its behavior, we need to find the derivative of the function, which will help us determine the intervals where the function is increasing or decreasing.

Finding the Derivative

To find the derivative of the function h(x) = x + 1/x, we will use the power rule and the quotient rule.

The Power Rule

The power rule states that if f(x) = x^n, then f'(x) = nx^(n-1).

The Quotient Rule

The quotient rule states that if f(x) = g(x)/h(x), then f'(x) = (h(x)g'(x) - g(x)h'(x)) / h(x)^2.

Applying the Power Rule and Quotient Rule

Using the power rule, we can find the derivative of x, which is 1.

Using the quotient rule, we can find the derivative of 1/x, which is -1/x^2.

Now, we can find the derivative of the function h(x) = x + 1/x by adding the derivatives of x and 1/x.

h'(x) = 1 - 1/x^2

Finding the Critical Points

To find the critical points, we need to set the derivative equal to zero and solve for x.

h'(x) = 1 - 1/x^2 = 0

Simplifying the equation, we get:

1 = 1/x^2

Multiplying both sides by x^2, we get:

x^2 = 1

Taking the square root of both sides, we get:

x = ±1

Therefore, the critical points are x = 1 and x = -1.

Analyzing the Intervals

To analyze the intervals, we need to test the sign of the derivative in each interval.

Interval 1: (-∞, -1)

In this interval, we can choose a test point, say x = -2.

h'(-2) = 1 - 1/(-2)^2 = 1 - 1/4 = 3/4 > 0

Since the derivative is positive, the function is increasing in this interval.

Interval 2: (-1, 1)

In this interval, we can choose a test point, say x = 0.

h'(0) = 1 - 1/0^2 is undefined

However, we can use the limit to determine the sign of the derivative.

lim x→0- h'(x) = lim x→0- (1 - 1/x^2) = -∞

Since the limit is negative, the derivative is negative in this interval.

Interval 3: (1, ∞)

In this interval, we can choose a test point, say x = 2.

h'(2) = 1 - 1/2^2 = 1 - 1/4 = 3/4 > 0

Since the derivative is positive, the function is increasing in this interval.

Conclusion

In conclusion, the graph of the function h(x) = x + 1/x is increasing in the intervals (-∞, -1) and (1, ∞) and decreasing in the interval (-1, 1). The critical points are x = 1 and x = -1, which are the turning points of the function.

Sketching the Graph

To sketch the graph, we need to plot the function and its turning points.

Plotting the Function

To plot the function, we can use a graphing calculator or software.

Plotting the Turning Points

To plot the turning points, we can use the critical points x = 1 and x = -1.

Conclusion

Final Answer

The final answer is:

The graph of the function h(x) = x + 1/x is increasing in the intervals (-∞, -1) and (1, ∞) and decreasing in the interval (-1, 1).
The critical points are x = 1 and x = -1, which are the turning points of the function.
Q&A: Analyzing the Function h(x) = x + 1/x =====================================================

Introduction

In our previous article, we analyzed the function h(x) = x + 1/x and found its increasing and decreasing intervals, as well as its turning points. In this article, we will answer some frequently asked questions about the function and its analysis.

Q: What is the domain of the function h(x) = x + 1/x?

A: The domain of the function h(x) = x + 1/x is all real numbers except x = 0, since the function is undefined at x = 0.

Q: How do you find the derivative of the function h(x) = x + 1/x?

A: To find the derivative of the function h(x) = x + 1/x, we use the power rule and the quotient rule. The derivative of x is 1, and the derivative of 1/x is -1/x^2. Therefore, the derivative of the function h(x) = x + 1/x is h'(x) = 1 - 1/x^2.

Q: What are the critical points of the function h(x) = x + 1/x?

A: The critical points of the function h(x) = x + 1/x are x = 1 and x = -1, which are found by setting the derivative equal to zero and solving for x.

Q: In which intervals is the function h(x) = x + 1/x increasing or decreasing?

A: The function h(x) = x + 1/x is increasing in the intervals (-∞, -1) and (1, ∞) and decreasing in the interval (-1, 1).

Q: What are the turning points of the function h(x) = x + 1/x?

A: The turning points of the function h(x) = x + 1/x are x = 1 and x = -1, which are the critical points of the function.

Q: How do you sketch the graph of the function h(x) = x + 1/x?

A: To sketch the graph of the function h(x) = x + 1/x, you need to plot the function and its turning points. You can use a graphing calculator or software to plot the function.

Q: What is the significance of the function h(x) = x + 1/x in mathematics?

A: The function h(x) = x + 1/x is a simple yet important function in mathematics. It is used to model real-world phenomena, such as population growth and chemical reactions. It is also used in calculus to illustrate the concept of limits and derivatives.

Conclusion

In conclusion, the function h(x) = x + 1/x is a simple yet important function in mathematics. Its analysis provides valuable insights into its behavior and its graph. We hope that this Q&A article has helped to clarify any questions you may have had about the function and its analysis.

Final Answer

The final answer is:

The domain of the function h(x) = x + 1/x is all real numbers except x = 0.
The derivative of the function h(x) = x + 1/x is h'(x) = 1 - 1/x^2.
The critical points of the function h(x) = x + 1/x are x = 1 and x = -1.
The function h(x) = x + 1/x is increasing in the intervals (-∞, -1) and (1, ∞) and decreasing in the interval (-1, 1).
The turning points of the function h(x) = x + 1/x are x = 1 and x = -1.
The graph of the function h(x) = x + 1/x can be sketched by plotting the function and its turning points.