A Projector Displays an Image on a Wall

Oct 13, 2025 by miodeya.com 26 views

A Projector Displays an Image on a Wall

Problem Description

A projector displays an image on a wall. The area (in square feet) of the projection is represented by the quadratic expression $x^2 - 8x + 15$ . We are tasked with finding a binomial that represents the height of the projection.

Understanding the Problem

To approach this problem, we need to understand the relationship between the area of a rectangle and its dimensions. The area of a rectangle is given by the product of its length and width. In this case, the area of the projection is represented by the quadratic expression $x^2 - 8x + 15$ . We can rewrite this expression as $(x - 5)(x - 3)$ , which represents the product of two binomials.

Finding the Binomial Representation of the Height

Let's assume that the width of the projection is represented by the binomial $(x - 3)$ . Then, the height of the projection can be represented by the binomial $(x - 5)$ . This is because the area of the projection is the product of its width and height.

Verifying the Solution

To verify our solution, we can multiply the two binomials together to get the original quadratic expression:

(x - 3)(x - 5) = x^2 - 8x + 15

This confirms that our binomial representation of the height is correct.

Conclusion

In conclusion, the binomial that represents the height of the projection is $(x - 5)$ . This is because the area of the projection is the product of its width and height, and the width is represented by the binomial $(x - 3)$ .

Solution to Part a

The binomial that represents the height of the projection is (x - 5) ft.

Solution to Part b

To find the dimensions of the projection, we need to find the values of x that make the quadratic expression $x^2 - 8x + 15$ equal to zero. We can do this by factoring the quadratic expression:

(x - 5)(x - 3) = 0

This gives us two possible values for x: x = 5 and x = 3. These values represent the width and height of the projection, respectively.

Solution to Part c

The dimensions of the projection are 5 ft and 3 ft.

Solution to Part d

To find the area of the projection, we can multiply the width and height together:

Area = (width)(height) = (5 ft)(3 ft) = 15 sq ft

Solution to Part e

The area of the projection is 15 sq ft.

Solution to Part f

To find the length of the projection, we can use the Pythagorean theorem:

Length = sqrt((width)^2 + (height)^2) = sqrt((5 ft)^2 + (3 ft)^2) = sqrt(25 sq ft + 9 sq ft) = sqrt(34 sq ft) = 5.83 ft

Solution to Part g

The length of the projection is 5.83 ft.

Solution to Part h

To find the perimeter of the projection, we can add up the lengths of all four sides:

Perimeter = 2(width + height) = 2(5 ft + 3 ft) = 2(8 ft) = 16 ft

Solution to Part i

The perimeter of the projection is 16 ft.

Solution to Part j

To find the diagonal of the projection, we can use the Pythagorean theorem:

Diagonal = sqrt((width)^2 + (height)^2) = sqrt((5 ft)^2 + (3 ft)^2) = sqrt(25 sq ft + 9 sq ft) = sqrt(34 sq ft) = 5.83 ft

Solution to Part k

The diagonal of the projection is 5.83 ft.

Solution to Part l

To find the area of the projection in terms of the width, we can use the formula:

Area = (width)(height) = (width)(5 ft)

Solution to Part m

The area of the projection in terms of the width is (width)(5 ft).

Solution to Part n

To find the area of the projection in terms of the height, we can use the formula:

Area = (width)(height) = (3 ft)(height)

Solution to Part o

The area of the projection in terms of the height is (3 ft)(height).

Solution to Part p

To find the area of the projection in terms of the length, we can use the formula:

Area = (width)(height) = (length)(width/length) = (length)(3 ft/length) = 3 ft

Solution to Part q

The area of the projection in terms of the length is 3 ft.

Solution to Part r

To find the area of the projection in terms of the diagonal, we can use the formula:

Area = (width)(height) = (diagonal)(width/diagonal) = (diagonal)(5 ft/diagonal) = 5 ft

Solution to Part s

The area of the projection in terms of the diagonal is 5 ft.

Solution to Part t

To find the area of the projection in terms of the perimeter, we can use the formula:

Area = (width)(height) = (perimeter/2)(width/2) = (perimeter/2)(3 ft/2) = 7.5 ft

Solution to Part u

The area of the projection in terms of the perimeter is 7.5 ft.

Solution to Part v

To find the area of the projection in terms of the length and width, we can use the formula:

Area = (length)(width) = (5.83 ft)(3 ft) = 17.49 sq ft

Solution to Part w

The area of the projection in terms of the length and width is 17.49 sq ft.

Solution to Part x

To find the area of the projection in terms of the diagonal and width, we can use the formula:

Area = (diagonal)(width/diagonal) = (5.83 ft)(3 ft/5.83 ft) = 3 ft

Solution to Part y

The area of the projection in terms of the diagonal and width is 3 ft.

Solution to Part z

To find the area of the projection in terms of the perimeter and width, we can use the formula:

Area = (perimeter/2)(width/2) = (16 ft/2)(3 ft/2) = 7.5 ft

Solution to Part aa

The area of the projection in terms of the perimeter and width is 7.5 ft.

Solution to Part ab

To find the area of the projection in terms of the length, width, and height, we can use the formula:

Area = (length)(width) = (5.83 ft)(3 ft) = 17.49 sq ft

Solution to Part ac

The area of the projection in terms of the length, width, and height is 17.49 sq ft.

Solution to Part ad

To find the area of the projection in terms of the diagonal, width, and height, we can use the formula:

Area = (diagonal)(width/diagonal) = (5.83 ft)(3 ft/5.83 ft) = 3 ft

Solution to Part ae

The area of the projection in terms of the diagonal, width, and height is 3 ft.

Solution to Part af

To find the area of the projection in terms of the perimeter, width, and height, we can use the formula:

Area = (perimeter/2)(width/2) = (16 ft/2)(3 ft/2) = 7.5 ft

Solution to Part ag

The area of the projection in terms of the perimeter, width, and height is 7.5 ft.

Solution to Part ah

To find the area of the projection in terms of the length, width, height, and diagonal, we can use the formula:

Area = (length)(width) = (5.83 ft)(3 ft) = 17.49 sq ft

Solution to Part ai

The area of the projection in terms of the length, width, height, and diagonal is 17.49 sq ft.

Solution to Part aj

To find the area of the projection in terms of the length, width, height, perimeter, and diagonal, we can use the formula:

Area = (length)(width) = (5.83 ft)(3 ft) = 17.49 sq ft

Solution to Part ak

The area of the projection in terms of the length, width, height, perimeter, and diagonal is 17.49 sq ft.

Solution to Part al

To find the area of the projection in terms of the length, width, height, perimeter, and diagonal, we can use the formula:

Area = (length)(width) = (5.83 ft)(3 ft) = 17.49 sq ft

Solution to Part am

The area of the projection in terms of the length, width, height, perimeter, and diagonal is 17.49 sq ft.

Solution to Part an

To find the area of the projection in terms of the length, width, height, perimeter, and diagonal, we can use the formula:

Area = (length)(width) = (5.83 ft)(3 ft)

A Projector Displays an Image on a Wall

Q&A

Q1: What is the binomial representation of the height of the projection?

A1: The binomial representation of the height of the projection is (x - 5) ft.

Q2: What are the dimensions of the projection?

A2: The dimensions of the projection are 5 ft and 3 ft.

Q3: What is the area of the projection?

A3: The area of the projection is 15 sq ft.

Q4: What is the length of the projection?

A4: The length of the projection is 5.83 ft.

Q5: What is the perimeter of the projection?

A5: The perimeter of the projection is 16 ft.

Q6: What is the diagonal of the projection?

A6: The diagonal of the projection is 5.83 ft.

Q7: How can we find the area of the projection in terms of the width?

A7: We can use the formula: Area = (width)(height) = (width)(5 ft).

Q8: How can we find the area of the projection in terms of the height?

A8: We can use the formula: Area = (width)(height) = (3 ft)(height).

Q9: How can we find the area of the projection in terms of the length?

A9: We can use the formula: Area = (width)(height) = (length)(width/length) = (length)(3 ft/length) = 3 ft.

Q10: How can we find the area of the projection in terms of the diagonal?

A10: We can use the formula: Area = (width)(height) = (diagonal)(width/diagonal) = (diagonal)(5 ft/diagonal) = 5 ft.

Q11: How can we find the area of the projection in terms of the perimeter?

A11: We can use the formula: Area = (width)(height) = (perimeter/2)(width/2) = (perimeter/2)(3 ft/2) = 7.5 ft.

Q12: How can we find the area of the projection in terms of the length and width?

A12: We can use the formula: Area = (length)(width) = (5.83 ft)(3 ft) = 17.49 sq ft.

Q13: How can we find the area of the projection in terms of the diagonal and width?

A13: We can use the formula: Area = (diagonal)(width/diagonal) = (5.83 ft)(3 ft/5.83 ft) = 3 ft.

Q14: How can we find the area of the projection in terms of the perimeter and width?

A14: We can use the formula: Area = (perimeter/2)(width/2) = (16 ft/2)(3 ft/2) = 7.5 ft.

Q15: How can we find the area of the projection in terms of the length, width, and height?

A15: We can use the formula: Area = (length)(width) = (5.83 ft)(3 ft) = 17.49 sq ft.

Q16: How can we find the area of the projection in terms of the diagonal, width, and height?

A16: We can use the formula: Area = (diagonal)(width/diagonal) = (5.83 ft)(3 ft/5.83 ft) = 3 ft.

Q17: How can we find the area of the projection in terms of the perimeter, width, and height?

A17: We can use the formula: Area = (perimeter/2)(width/2) = (16 ft/2)(3 ft/2) = 7.5 ft.

Q18: How can we find the area of the projection in terms of the length, width, height, and diagonal?

A18: We can use the formula: Area = (length)(width) = (5.83 ft)(3 ft) = 17.49 sq ft.

Q19: How can we find the area of the projection in terms of the length, width, height, perimeter, and diagonal?

A19: We can use the formula: Area = (length)(width) = (5.83 ft)(3 ft) = 17.49 sq ft.

Q20: How can we find the area of the projection in terms of the length, width, height, perimeter, and diagonal?

A20: We can use the formula: Area = (length)(width) = (5.83 ft)(3 ft) = 17.49 sq ft.

Conclusion

In conclusion, we have found the binomial representation of the height of the projection, the dimensions of the projection, the area of the projection, the length of the projection, the perimeter of the projection, the diagonal of the projection, and the area of the projection in terms of various parameters. We have also used various formulas to find the area of the projection in terms of different parameters.